Astronomy Navigational question

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Astronomy Navigational question

Please show all work. For the following problem:

Latitude=90-solar altitude + Declination of the Sun
Longitude = (UTC clock noon time– 1200) x 15 degrees
Solar DEC: Mar 21= 0 degrees JUN 21= 23.5 degrees
Sep 21 = 0 degrees Dec 21 = – 23.5 degrees

A ships navigator takes Sun shots and determines that the altitude of the Sun at noon is 27.5 degrees. The date is September 21, the autumnal equinox, when the Sun’s declination is 0 degrees. What is the latitude of the ship?The post Astronomy Navigational question first appeared on cipdpro.co.uk .Astronomy Navigational question was first posted on December 12, 2023 at 4:17 am.©2019 "cipdpro.co.uk ". Use of this feed is for personal non-commercial use only. If you are not reading this article in your feed reader, then the site is guilty of copyright infringement. Please contact me at admin@cipdpro.co.uk

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