2/ 11/19 IND = 2 0 1 2 – 14 – *^ Ave next Ca H 10 03 # of C

in /by

2/ 11/19 IND = 2 0 1 2 – 14 – *^ Ave next Ca H 10 03 # of C

Can I obtain help on this NMR/IR Spectrum? I would like to know the chemical shift, analysis, what’s the possible equation/formula.
2/ 11/19IND = 2 0 1 2 – 14 – *^Ave nextCa H 10 03# of C = Finteasing of Cantil ] x ( 100^IND : 21 4 1 + 2 – 10 – 0~ intensity of MT1 / D = ‘ 6 + 2 – 10 : 1 = 5 ring3 / 19 / 193 4ZKHI100d90 .80 .70 .60 .%/0 Transmittance50 .40 -4 . 14.030 -$10 :3120 41. 5 7C – 11LIL4000350030002500200015001000`50043 12 11 10 9 8 7 6 52Wavenumbers jom -"!Chemical shift ( ppm )C – Hsinglet ( Z H) #+ 7C – HSinglet [ 24) at B0triplet ( 4 40 ) at 4- C – OHat 12200175150125100755025Chemical shift ( ppm )- 0 – cl/2 – 6- OH

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